7x/10-2x+5/3x^2-5x

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Solution for 7x/10-2x+5/3x^2-5x equation: 


x in (-oo:+oo)

(5/3)*x^2+(7*x)/10-(2*x)-(5*x) = 0

(5/3)*x^2+(7*x)/10-2*x-5*x = 0

5/3*x^2-63/10*x = 0

DELTA = (-63/10)^2-(0*5/3*4)

DELTA = 3969/100

DELTA > 0

x = ((3969/100)^(1/2)+63/10)/(5/3*2) or x = (63/10-(3969/100)^(1/2))/(5/3*2)

x = 189/50 or x = 0

x in { 0, 189/50 }

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